Woodbury County topographic maps
Click on a map to view its topography, its elevation and its terrain.
Sioux City
United States > Iowa > Woodbury County
Sioux City is located at 42°29′44″N 96°23′26″W / 42.495668°N 96.390525°W / 42.495668; -96.390525.[1] Sioux City lies at an altitude of 1,135 ft (345.9 m) above sea level. Sioux City borders two states, South Dakota to the west-northwest and Nebraska to the west. According to the United…
Average elevation: 352 m
