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Jackson
United States > Wyoming > Teton County
Jackson is located at an elevation of 6,237 feet (1,901 m) above sea level. According to the United States Census Bureau, the town has a total area of 2.95 square miles (7.64 km2), of which 2.91 square miles (7.54 km2) is land and 0.04 square miles (0.10 km2) is water.
Average elevation: 2,043 m