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Village of Alfred topographic map

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About this map

Name: Village of Alfred topographic map, elevation, terrain.

Location: Village of Alfred, Town of Alfred, Allegany County, New York, 14802, United States (42.24229 -77.80322 42.26576 -77.77802)

Average elevation: 597 m

Minimum elevation: 494 m

Maximum elevation: 686 m

The elevation of Alfred is about 1,700 feet (520 m) but rises to a high point of 2,355 feet (718 m) at the summit of Jericho Hill just south of the village. The hills greatly affect the weather in the region, which results in quick changes as well as different conditions in neighboring valleys.

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